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4x-3y=17⇒×3⇒ 12x - 9y=51
------------------- -
⇔37y=37
⇔y=1
substitusi y=1 ke 3x+7y=22 ⇔ 3x+7(1)=22 ⇔ 3x=22-7 ⇔3x=15 ⇔x=5
nilai dari 5x+8y= 5(5)+8(1)= 25+8=33
4x - 3y = 17 |3|
12x + 28y = 88
12x - 9y = 51 -
37y = 37
y = 1
* 3x + 7y = 22
3x + 7(1) = 22
3x = 15
x = 5
⇔ 5x + 8y
5(5) + 8(1)
25 + 8 = 33