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didapat ac = √20 = 2√5
cos C = bc/ac = 4/2√5 = 2/√5 = 2√5/5
2. (sin 30° × cos 30°) + (sin 60° × cos 60°) = n
(1/2 × √3/2) + (√3/2 × 1/2) = n
2√3/4 = n
n"+1 = (2√3/4)" + 1
= {(4×3)/16} + 16/16
= 12/16 + 16/16
= 28/16