Question

1. Diketahui persamaan kuadrat x pangkat 2 - 4x - (p+2) = 0, akar akarnya x1 dan x2. tentukan niai p jika :

a. x1=x2
b. 3x1= x2-8
c. x1x2= -1
d. x1=0

tolong jawab ya.., pakai cara

Answer 1

A. x1 = x2
x1 - x2 = 0
√D/a = 0
-4² - 4(1)(-p-2) / 1= 0
16 + 4p + 8 = 0
4p = - 24
p = -6
c. x1.x2 = -1
c/a = -1
-(p+2) = -1
p + 2 = 1
p = -1
d. x1 = 0
0² - 4(0) - (p+2) = 0
-(p+2) = 0
-p - 2 = 0
p = -2