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a. f(2) = ...? dan f(3)...?
f(2) = -2.2 + 3 = -4 + 3 = -1
f(3) = -2.3 + 3 = -6 + 3 = -3
b. f(a) = -7
-2a + 3 = -7
3 + 7 = 2a
10 = 2a
5 = a
f(x) = ax + b
f(-3) = -15
f(-3) = -3a + b
-3a + b = -15....(1)
f(3) = 9
3a + b = 9...(2)
eliminasi (1) dan (2) diperoleh a = 4, b = - 3
f(x) = ax + b = 4x - 3
f(-2) + f(2) = {(4.(-2) - 3) + (4.2 - 3)} = {(-8 - 3) + (8 - 3)} = (-11 + 5) = -6