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f(3)=1 -> 3(2)+b=1
f(1)=-1 -> 1(2)+b=-1 (dikurang)
4 : 2 = 2 (a)
a=2 disubstitusikan ke 3(2)+b=1
3(2)×2+b=1
6×2+b=1
b=1-12=-11
B. (saya tidak tahu)
C.f(x)=2x+b
f(-2)=2(-2)+(-11)
=-4+(-11)=-15