Question

1. diketahui 2log5 = p. nilai 20log125 adalah...
2. diketahui 5log3 = a dan 3log4 = b. nilai 4log15 adalah...
3. diketahui 2logakar12x+4 = 3. Nilai 3x adalah....

Answer 1

1. ^20log125 = ^2log 125/^2log 20
^2log5^3/(^2log4+^2log5)=3*^2log5/(2^2log2+^2log5) = 3p/(2+p)

2. ^4Log15 = ^5log15/^5log4 = ^5log3.5/^5log4=(^5log3+^5log5)/(^5log3*^3log4)=(a+1)/ab

3. 2^3= akar 12x+4
(2^3)^2 = (akar 12x+4)2
64 = 12x+4
12x=60
x= 5
3x= 3*5 = 15