Question

Lim_{x \to0} 2x .tan3x / 1- cos^{2}

Answer 1

Lim x->0  2x tan(3x)/(1 - cos^2 (x))
= lim x->0  2x tan(3x)/sin^2 (x)
= lim x->0  2x/sin(x) * lim x->0 tan(3x)/sin(x)
= 2 * 3
= 6