Question

1. Berapakah nilai ∛√2¹² ?
2. Jika logX + logY = Z, maka nilai X adalah?

Answer 1

1.∛2¹² = 2^(12 : 3) = 2⁴ = 16
2. log x + log y = z
   log xy = z
   log xy = log 10^z
         xy = 10^z
         x   = 10^z /y