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x⇒1 1 - √x x⇒1 (1 - √x)(1 + √x)
= lim - (1 - x)(1 + √x)
x⇒1 (1 - x)
= lim - (1 + √x)
x⇒1
= - (1 + √1)
= - (1 + 1)
= - 2