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3x + 8y = 34 ....II
para encontrar y
(5x + 6y = 20) x3 ---> 15 x + 18y = 60
(3x + 8y = 34) x5 ---> 15 x + 40y = 170
se cancelan los x=
22y= 110
y= 5
reemplazamos y en ...I
5x + 6(5) = 20
5x = -10
x= -2