Question

1. 3x^2 + 26x -9 = 0
2. -4x^2 + 24x – 11 = 0
Tolong dikerjakan menggunakan rumus ABC

Answer 1

1.
X1dan2 = -b +- akar b kuadrat - 4ac dibagi 2a

dik a = 3 b =26 c = -9
= -26  +- 26.26 - 4.3.(-9) / 2.3
= -26 +- 676 + 108 / 6
= -26 +- 784 / 6
= -26 +- akar 784 / 6
= -26 +-  akar 196 x akar 4 /6
= -26 +- 14 + 2 / 6
= -26 +- 16 / 6
X1 = -26 + 16 / 6 = 10 /6
X2 = -26 - 16 /6 = 42/6 = 8


2. = -24 +- akar 24.24 - 4.(-4).(-11) / 2.-4
= -24 +- akar 576 -176 / (-8)
= -24 +-  akar 400 /(-8)
= -24 +- 20 / -8
X1 = -24 + 20 / -8 = 1/2
X2 = -24 - 20 /-8 = 6