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3x=5+y
x=5+y / 3
sustitución:
2x+y=20
2(5+y / 3) + y = 20
10+2y / 3 + y = 20
10+2y+3y=20(3)
10+ 5y = 60
5y = 60 - 10
5y= 50
y = 10
ahora hallamos x
3x - y =5
3x - 10 = 5
3x = 5 + 10
3x = 15
x = 5
comprobamos su validez
3x-y=5
3(5)-10=5
15-10=5
5=5