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Verified answer
Integral.Nomor 1
∫ (3x² + 2 sin x) dx
= 3x²⁺¹ / (2 + 1) + 2 (-cos x) + C
= x³ - 2 cos x + C
Nomor 2
∫ (2 - 4 sin x) dx
= 2x - 4(-cos x) dx
= 2x + 4 cos x + C