Question

1. 3 log 27 + 2 log 1 per 8 =
2. 4 log 16 x 2 log 1 per 2 =
3. log 108 =
4. 2 log 12 + 2 log 1 per 2 - 2 log 3 =

Answer 1

1)
³log 27 + ²log 1/8
³log 27 + ²log 2⁻³
3 + (-3)
0

2)
⁴log 16 x ²log 1/2
⁴log 16 x ²log 2⁻¹
2 x -1 
-2

3)
log 108
log (27 x 4)
log 27 + log 4

4)
²log 12 + ²log 1/2 - ²log 3
²log (12 x 1/2 : 3)
²log 2
1

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