Question

1) 2√x-1 < 1
2) (x^2)^x = x^4x-x^2
To long dibantuu ya

Answer 1

Verified answer

1.
2√x-1 < 1
(√x-1 < 1/2)²
x-1 < 1/4
x < 1 + 1/4
x < 5/4

x _> 0

Hp ={ 0<_ x < 5/4}

2.
(x^2)^x = x^4x-x^2
x^2x = x^4x-x²
2x = 4x - x²
x² - 2x = 0
x(x-2) = 0
x = 0 V x = 2