Respuesta:
27x
0x
Explicación paso a paso:
Corona porfa
[tex]({(2x + 1)}^{3} = ({2x})^{3} + 3( {2x})^{2}(1) + 3(2x)( {1})^{2} + ({1})^{3} = {8x}^{3} +3( {4x}^{2} ) + (6x) + 1 = {2x}^{3} + 12 {x}^{2} + 6x + 1 \\ \\{ (1 - x)}^{3} = {(1)}^{3} - 3( {1})^{2} ( - x) + 3(1)( { - x})^{2} - ( { - x})^{3} = 1 - 3(1)( - x) + 3( {x})^{2} - ( { - x}^{3} ) = 1 + 3x + 3 {x}^{2} + {x}^{3} [/tex]
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Verified answer
Respuesta:
27x
0x
Explicación paso a paso:
Corona porfa
Explicación paso a paso:
[tex]({(2x + 1)}^{3} = ({2x})^{3} + 3( {2x})^{2}(1) + 3(2x)( {1})^{2} + ({1})^{3} = {8x}^{3} +3( {4x}^{2} ) + (6x) + 1 = {2x}^{3} + 12 {x}^{2} + 6x + 1 \\ \\{ (1 - x)}^{3} = {(1)}^{3} - 3( {1})^{2} ( - x) + 3(1)( { - x})^{2} - ( { - x})^{3} = 1 - 3(1)( - x) + 3( {x})^{2} - ( { - x}^{3} ) = 1 + 3x + 3 {x}^{2} + {x}^{3} [/tex]