Respuesta:
[tex]1) [(-2)⁴]² = {( - 2)}^{4 \times 2} = {( - 4)}^{8} [/tex]
[tex]2) \frac{ {2}^{4} \times {2}^{3} \times {2}^{3} }{ {2}^{3} \times {2}^{5} } = \frac{ {2}^{4 + 3 + 3} }{ {2}^{3 + 5} } = \frac{ {2}^{10} }{ {2}^{8} } = {2}^{10 - 8} = {2}^{2} = 4[/tex]
[tex]3) (4+5⁵+8⁹)⁰ = 1[/tex]
Explicación paso a paso:
[tex] {a}^{0} = 1[/tex]
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Verified answer
Respuesta:
[tex]1) [(-2)⁴]² = {( - 2)}^{4 \times 2} = {( - 4)}^{8} [/tex]
[tex]2) \frac{ {2}^{4} \times {2}^{3} \times {2}^{3} }{ {2}^{3} \times {2}^{5} } = \frac{ {2}^{4 + 3 + 3} }{ {2}^{3 + 5} } = \frac{ {2}^{10} }{ {2}^{8} } = {2}^{10 - 8} = {2}^{2} = 4[/tex]
[tex]3) (4+5⁵+8⁹)⁰ = 1[/tex]
Explicación paso a paso:
[tex] {a}^{0} = 1[/tex]