Question

1. 10a pangkat2 b pangkat4 c pangkat3 : 2 abc =
2. 6x pangkat3 y pangkat7 : 2xy : 3y =
3. 20 a pangkat4 b pangkat5 c pangkat7 : (4a pangkat2 b pangkat2 c pangkat2 : 2 abc ) =


dengn caranya ya

Answer 1

1. 10a²b⁴c³ : 2abc = 5ab³c²
Caranya :
=> 10 : 2 = 5
=> a² : a = a²⁻¹ = a
=> b⁴ : b = b⁴⁻¹ = b³
=> c³ : c = c³⁻¹ = c²
= 5ab³c²

2. 6x³y⁷ : 2xy : 3xy = xy⁵
Caranya :
=> 6 : 2 : 3 = 1
=> x³ : x : x = x³⁻¹⁻¹ = x
=> y⁷ : y : y = y⁷⁻¹⁻¹ = y⁵
= xy⁵

3. 20a⁴b⁵c⁷ : (4a²b²c² : 2abc) = 10a³c⁶
Caranya :
=> 20 : (4 : 2) = 20 : 2 = 10
=> a⁴ (a² : a) = a⁴ : a²⁻¹ = a⁴ : a = a⁴⁻¹ = a³
=> c⁷ : (c² : c) = c⁷ : c²⁻¹ = c⁷ : c = c⁷⁻¹ = c⁶
= 10a³c⁶