Odpowiedź:
c = 5 cm
b = 4 cm
h = 4 cm
a = x + b + x = x + 4 + x
Z Tw. Pitagorasa 4² + x² = 5² ⇒ x² = 25 - 16 = 9
x = √9 = 3
a = 3 + 4 + 3 = 10
-------------------------
a) Obwód trapezu: L = a + b +2 c = [ 10 + 4 + 2*5 ] cm = 24 cm
Przekątna trapezu - p
Mamy p² = h² + ( b + x)² = 4² + 7² = 16 + 49 = 65
p = [tex]\sqrt{65}[/tex]
p = [tex]\sqrt{65}[/tex] cm
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b) tg α = [tex]\frac{h}{b + x} = \frac{4}{7}[/tex] ≈ 0,5714
więc α ≈ 30°
tg β = [tex]\frac{h}{x} = \frac{4}{3}[/tex] ≈ 1,3333
więc β ≈ 53°
zatem √ = β - α ≈ 53° - 30° = 23°
Odp. 30° i 23°
--------------------------
c) [tex]\frac{y}{h - y} = \frac{b}{a}[/tex]
[tex]\frac{y}{4 - y} = \frac{4}{10}[/tex]
10 y = 16 - 4 y
14 y = 16
y = [tex]\frac{16}{14} = \frac{8}{7}[/tex] więc h - y = 4 - [tex]\frac{8}{7} = \frac{28}{7} - \frac{8}{7} = \frac{20}{7}[/tex]
tg Ф = [tex]\frac{0,5 a}{h - y} = \frac{5}{\frac{20}{7} } = 5* \frac{7}{20} = \frac{35}{20} = 1,75[/tex]
Ф ≈ 60°
zatem ω = 180° - 2 Ф = 180° - 120° ≈ 60°
Odp. 60°
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Odpowiedź:
c = 5 cm
b = 4 cm
h = 4 cm
a = x + b + x = x + 4 + x
Z Tw. Pitagorasa 4² + x² = 5² ⇒ x² = 25 - 16 = 9
x = √9 = 3
a = 3 + 4 + 3 = 10
-------------------------
a) Obwód trapezu: L = a + b +2 c = [ 10 + 4 + 2*5 ] cm = 24 cm
Przekątna trapezu - p
Mamy p² = h² + ( b + x)² = 4² + 7² = 16 + 49 = 65
p = [tex]\sqrt{65}[/tex]
p = [tex]\sqrt{65}[/tex] cm
----------------
b) tg α = [tex]\frac{h}{b + x} = \frac{4}{7}[/tex] ≈ 0,5714
więc α ≈ 30°
tg β = [tex]\frac{h}{x} = \frac{4}{3}[/tex] ≈ 1,3333
więc β ≈ 53°
zatem √ = β - α ≈ 53° - 30° = 23°
Odp. 30° i 23°
--------------------------
c) [tex]\frac{y}{h - y} = \frac{b}{a}[/tex]
[tex]\frac{y}{4 - y} = \frac{4}{10}[/tex]
10 y = 16 - 4 y
14 y = 16
y = [tex]\frac{16}{14} = \frac{8}{7}[/tex] więc h - y = 4 - [tex]\frac{8}{7} = \frac{28}{7} - \frac{8}{7} = \frac{20}{7}[/tex]
tg Ф = [tex]\frac{0,5 a}{h - y} = \frac{5}{\frac{20}{7} } = 5* \frac{7}{20} = \frac{35}{20} = 1,75[/tex]
Ф ≈ 60°
zatem ω = 180° - 2 Ф = 180° - 120° ≈ 60°
Odp. 60°
-------------------
Szczegółowe wyjaśnienie: