Zredukuj do najprostszej postaci:
a) x-2(x+1)[x+2(x+1)]=
b)(x+2)[6(x+4)-5(x+6)]=
^ - do potęgi 2
a) x-2(x+1)[x+2(x+1)] = x-2(x+1)[3x+2] =x-2(3x^ +2x +3x +2) = x-6x^-4x-6x-4 = -9x-6x^ -4 =
-(9x+6x^ +4)
b) (x+2)[6(x+4)-5(x+6)] = (x+2)[6x+24-5x-30] = (x+2)[x-6] = x^-6x+2x-12 = x^-4x-12
Mam nadzieję, że pomogłam.
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^ - do potęgi 2
a) x-2(x+1)[x+2(x+1)] = x-2(x+1)[3x+2] =x-2(3x^ +2x +3x +2) = x-6x^-4x-6x-4 = -9x-6x^ -4 =
-(9x+6x^ +4)
b) (x+2)[6(x+4)-5(x+6)] = (x+2)[6x+24-5x-30] = (x+2)[x-6] = x^-6x+2x-12 = x^-4x-12
Mam nadzieję, że pomogłam.