Znajdz trzynasty wyraz ciągu arytmetycznego jeśli
A. a₁= -1 r=3
B. a₁= 10 r=-2
C. a₂=3 a₆=4
potem do tego trzeba rozwiązać z układu równań
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a)
a₁ = -1
r = 3
a₁₃ = a₁ + 12r
a₁₃ = -1 + 12 x 3 = 35
b)
a₁ = 10
r = -2
a₁₃ = a₁ + 12r
a₁₃ = 10 + 12 x (-2) = -14
c)
a₂ = 3
a₆ = 4
a₂ = a₁ + r
a₆ = a₁ + 5r
3 = a₁ + r
4 = a₁ + 5r
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-1 = 4r
r = -0,25
3 = a₁ + (-0,25)
a₁ = 3,25
a₁₃ = a₁ + 12
a₁₃ = 3,25 + 12 x (-0,25) = 0,25
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