Znajdź środek i promień okręgu o równaniu.
x²+y²-2ax-2by+c=0
-2a=-4
a=-4;-2
a=2
.........
-2b=6
b=6;(-2)
b=-3
............
c=-12
S=(a,b)
S=(2;-3)
r²=2²+(-3)²+12
r=√25
r=5=promień
x^2 + y^2 - 2ax - 2by + a^2 + b^2 - r^2 = 0 ----- wzór
c = a^2 + b^2 - r^2
-2a = -4
a = 2
-2b = 6
b = -3
S = (a,b ) = (2,-3) --- środek
a^2 + b^2 - r^2 = c
2^2 + (-3)^2 - r ^2= -12
4 + 9 - r^2 = -12
13 + 12 = r^2
25 = r^2
r = 5 --- promień
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x²+y²-2ax-2by+c=0
-2a=-4
a=-4;-2
a=2
.........
-2b=6
b=6;(-2)
b=-3
............
c=-12
S=(a,b)
S=(2;-3)
r²=2²+(-3)²+12
r=√25
r=5=promień
x^2 + y^2 - 2ax - 2by + a^2 + b^2 - r^2 = 0 ----- wzór
c = a^2 + b^2 - r^2
-2a = -4
a = 2
-2b = 6
b = -3
S = (a,b ) = (2,-3) --- środek
a^2 + b^2 - r^2 = c
2^2 + (-3)^2 - r ^2= -12
4 + 9 - r^2 = -12
13 + 12 = r^2
25 = r^2
r = 5 --- promień