4y-3/6+3<3y/2+5/8 proszę o pomoc ta / znaczy ułamek,w pierwszym 4y-3ma być całe po ułamkiem
(4y-3)/6 + 3 < 3y/2 + 5/8 |*24
4(4y-3)+3*24 < 12*3y+5*3
16y-12+72 < 36y+15
16y-36y < 15+12-72
-20y < -45 |:(-20)
y > 9/4
Odp. y∈(9/4, ∞)
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(4y-3)/6 + 3 < 3y/2 + 5/8 |*24
4(4y-3)+3*24 < 12*3y+5*3
16y-12+72 < 36y+15
16y-36y < 15+12-72
-20y < -45 |:(-20)
y > 9/4
Odp. y∈(9/4, ∞)