zmien postac ogolna funkcji kwadratowej y=x^2-x-2 na postac kanoniczna potrzebuje na jutro pomocy
Δ=(-1)²-4*1*(-2)= 1+8=9
√9=3
p=1/2
q=-9/4
y=(x-1/2)²-9/4
y = x^2 - x - 2
a = 1, b = - 1, c = -2
zatem
p = - b/(2a) = 1/2
q = ( 1/2)^2 - 1/2 - 2 = 1/4 - 2/4 - 8/4 = - 9/4 = - 2 1/4
y = a*(x - p)^2 + q
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więc
Odp. y = ( x - 1/2)^2 - 2 1/4 - postać kanoniczna
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Δ=(-1)²-4*1*(-2)= 1+8=9
√9=3
p=1/2
q=-9/4
y=(x-1/2)²-9/4
y = x^2 - x - 2
a = 1, b = - 1, c = -2
zatem
p = - b/(2a) = 1/2
q = ( 1/2)^2 - 1/2 - 2 = 1/4 - 2/4 - 8/4 = - 9/4 = - 2 1/4
y = a*(x - p)^2 + q
=====================
więc
Odp. y = ( x - 1/2)^2 - 2 1/4 - postać kanoniczna
=====================================================