Zawsze jest tak, jak w tych przypadkach:(x-1)2=(1-x)2,(2x-2)2=(2-2x)2 ?
(x-1)²=(1-x)²
x-1=1-x
x+x=1+1
2x=2|:2
x=1
(2x-2)²=(2-2x)²
2x-2=2-2x
2x+2x=2+2
4x=4|:4
(x-1)^2=(1-x)^2
x^2-2x+1=1-2x+x^2
x^2-x^2-2x+2x+1-1=0
0=0
(2x-2)^2=(2-2x)^2
4x^2-8x+4=4-8x+4x^2
4x^2-4x^2-8x+8x+4-4=0
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
(x-1)²=(1-x)²
x-1=1-x
x+x=1+1
2x=2|:2
x=1
(2x-2)²=(2-2x)²
2x-2=2-2x
2x+2x=2+2
4x=4|:4
x=1
(x-1)^2=(1-x)^2
x^2-2x+1=1-2x+x^2
x^2-x^2-2x+2x+1-1=0
0=0
(2x-2)^2=(2-2x)^2
4x^2-8x+4=4-8x+4x^2
4x^2-4x^2-8x+8x+4-4=0
0=0