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C₂H₅OH + O₂ --bakterie---> CH₃COOH + H₂O
teraz otrzymujemy octan etylu
CH₃COOH + C₂H₅OH ---H⁺----> CH₃COOC₂H₅ + H₂O
CH3-CH2-OH + CH3COOH ---[H+]---> CH3-CH2-OOC-CH3 + H2O