Zapisz w postaci sumy algebraicznej:
c) 2x²(x - 5) - 3x(x² - 3x + 5) =
d) 6( a² + b +⅓ ) - 6(a² - ½) - 3( b + ⅓) =
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c) 2x²(x - 5) - 3x(x² - 3x + 5) =2x³-10x²-3x³+9x²-15x=-x³-x²-15x
d) 6( a² + b +⅓ ) - 6(a² - ½) - 3( b + ⅓) =6a²+6b+2-6a²+3-3b-1=
=3b+4