Zapisz w postaci sumy algebraicznej:
a)(2+b)do 3
b)(p_0,1)do 3
c) (x kreska ulamkowa w mianowniku 2 ) + 4) do 3
d) (5v i - jedna piata)do 3
e) (1 w mianowniku w + 3w)do 3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)(2+b)do 3=(2+b)³=(2+b)(2+b)²=(2+b)(4+4b+b²)=
=8+8b+2b²+4b+4b²+b³=8+12b+6b²+b³
b)(p_0,1)do 3=(p-0,1)³=(p-0,1)(p-0,1)²=
=(p-0,1)(p²-0,2p+0,01)=p³-0,2p²+0,01p-0,1p²+0,02p-0,001=
=p³0,3p²+0,03p-0,001
c) (x kreska ulamkowa w mianowniku 2 ) + 4) do 3=
=((x/2)+4)((x/2+4)²=(x/2+4)(x²/4+4x+16)=
=x³/8+2x²+8x+x²+16x+64=
=x³/8+3x²+24x+64
d) (5v i - jedna piata)do 3=
=(5v-1/5)(5v-1/5)²=(5v-1/5)(25v²-2v+1/25)=
=125v³-10v²+1/5v-5v²+2/5v-1/125=
=125v³-15v²+3/5v-1/125
e) (1 w mianowniku w + 3w)do 3=
= (1/w+3w)(1/w+3w)²=
=(1/w+3w)(1/w²+6+9w²)=
=1/w³+6/w+9w+3/w+18w+27w³=
=1/w³+9/w+27w+27w³
licze na naj