Zapisz w postaci sumy algebraicznej pole trójkąta o podstawie x+3 i wysokości x-3.
POMOCY
P = 0,5ah
a = x+3
h = x-3
P = 0,5(x+3)(x-3) = 0,5(x²-9) = 0,5x² - 4,5
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
P - pole trójkąta
P = 1/2 * a * h
a= x+3
h=x-3
P=1/2 *(x+3)*(x-3)
P=1/2 *(x^2 -9)
P=0,5x^2 -4,5
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P = 0,5ah
a = x+3
h = x-3
P = 0,5(x+3)(x-3) = 0,5(x²-9) = 0,5x² - 4,5
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
P - pole trójkąta
P = 1/2 * a * h
a= x+3
h=x-3
P=1/2 *(x+3)*(x-3)
P=1/2 *(x^2 -9)
P=0,5x^2 -4,5