Zapisz w postaci sumy algebraicznej: ( 2a - 3 ) ( 4a^2 + 6a + 9 )
( 2a - 3 ) ( 4a² + 6a + 9 )=8a³+12a²+18a-14a²-18a-27=8a³-2a²-27
(2a-3)(4a²+6a+9)=8a³+12a²+18a-12a²-18a-27=8a³-27
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( 2a - 3 ) ( 4a² + 6a + 9 )=8a³+12a²+18a-14a²-18a-27=8a³-2a²-27
(2a-3)(4a²+6a+9)=8a³+12a²+18a-12a²-18a-27=8a³-27