Question

zapisz w postaci sum algebra i oblicz (stos wz. skr . mnozenia)

3(4x-y)^2+4(x+3y)^2-2(x+y)(x-y)= gdy x=-0,1 y=0,2

Answer 1

3(4x-y)²+4(x+3y)²-2(x+y)(x-y)=3[16x²-8xy+y²]+4[x²+6xy+9y²]-2(x²-y²)=

=48x²-24xy+3y²+4x²+24xy+36y²-2x²+2y²=50x²+41y²

wartość dla x=-0,1  y=0,2

50x²+41y²=50*(-0,1)²+41*(0,2)²=50*0,01+41*0,04=0,5+1,64=2,14

 

Wzory:

Answer 2