zapisz w postaci kanonicznej .
a) y=x^2+6x+9
b)y=3x^2-6x+3
c) y=x^2+4x-1
d) y=2x^2+4x+6
e) y=3x^2-12x+7
p=-b/2a = -6/2 = -3
q=f(p)= 9-18+9 = 0
y=(x+3)^
p= 6/6= 1
q= 3-6+3 = 0
y=3(x-1)^
p= -4/2= -2
q= 4-8+1 = -3
y=(x+2)^ -3
p= -4/4=-1
q= 2-4+6 = 4
y=2(x+1)^ +4
p= 12/6= 2
q= 3*4 -24 +7 = 12- 17 = -5
y=3(x-2)^ -5
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a) y=x^2+6x+9
p=-b/2a = -6/2 = -3
q=f(p)= 9-18+9 = 0
y=(x+3)^
b)y=3x^2-6x+3
p= 6/6= 1
q= 3-6+3 = 0
y=3(x-1)^
c) y=x^2+4x-1
p= -4/2= -2
q= 4-8+1 = -3
y=(x+2)^ -3
d) y=2x^2+4x+6
p= -4/4=-1
q= 2-4+6 = 4
y=2(x+1)^ +4
e) y=3x^2-12x+7
p= 12/6= 2
q= 3*4 -24 +7 = 12- 17 = -5
y=3(x-2)^ -5