zapisz w najprostszej postaci wyrazenie; -[3x-1]-1[-2xdo pot.2-13x+1]+[3+x]do pote.2
Chyba o to chodziło ;-)
-[3x-1]-1[-2x^2-13x+1]+[3+x]^2= -3x+1+2x^2+13x-1+9+6x+x^2= 16x+9+3x^2
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Chyba o to chodziło ;-)
-[3x-1]-1[-2x^2-13x+1]+[3+x]^2= -3x+1+2x^2+13x-1+9+6x+x^2= 16x+9+3x^2