zamienic sume na iloczyn :
a) 8(x-4)-x+4+(3x-12)x
b)-9x2+30x-25
c)x2-8x-(x-8)(4x-1)
a) 8(x-4)-x+4+(3x-12)x =
= 8(x -4) -1(x -4) + 3x(x -4) =
= (x-4)*( 8 -1 +3x) =
= (x -4)*(3x +7)
b)-9x²+30x-25 =
= -( 9x² - 30x +25 ) =
= -( 3x - 5)²
c)x²-8x-(x-8)(4x-1)=
= x(x -8) - (x -8)(4x -1) =
= (x-8)*[ x - ( 4x -1)] =
= (x -8)*(x -4x +1) =
= (x-8)*( -3x +1)
W przykładzie b stosuję wzór skróconego mnożenia :
(a-b)²=a²-2ab+b²
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zamienic sume na iloczyn :
a) 8(x-4)-x+4+(3x-12)x =
= 8(x -4) -1(x -4) + 3x(x -4) =
= (x-4)*( 8 -1 +3x) =
= (x -4)*(3x +7)
b)-9x²+30x-25 =
= -( 9x² - 30x +25 ) =
= -( 3x - 5)²
c)x²-8x-(x-8)(4x-1)=
= x(x -8) - (x -8)(4x -1) =
= (x-8)*[ x - ( 4x -1)] =
= (x -8)*(x -4x +1) =
= (x-8)*( -3x +1)
W przykładzie b stosuję wzór skróconego mnożenia :
(a-b)²=a²-2ab+b²