Zamień system dziesiątkowy na dwójkowy i odwrotnie ( ze wszystkimi obliczeniami):
111 (2) , 101110001 (2) , 10011001 (2)
99 , 155, 1299
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111 => 7 bo 2^0+2^1+2^2=7
101110001 => 369 bo 2^0+2^4+2^5+2^6+2^8=369
10011001 => 153 bo 2^0+2^3+2^4+2^7=153
99 => 1100011 bo 2^0+2^1+2^5+2^6=99
115 => 1110011 bo 2^0+2^1+2^4+2^5+2^6=115
1299 => 10100010011 bo 2^0+2^1+2^4+2^8+2^10=1299
111₂=1×2⁰+1×2¹+1×2²=1+2+4=7
101110001₂=1× 2⁰+0×2¹+0×2²+0×2³+1x2⁴+1x2⁵+1x2⁶+0x2⁷+1x2⁸=
=1+0+0+0+16+32+64+0+ 256=369
10011001₂ =1x2⁰+0x2¹+0x2²+1x2³+1x2⁴+0x2⁵+0x2⁶+1x2⁷=
=1+0+0+8+16+0+0+128=153
99:2= 49 I 1
49:2= 24 I 1
24:2=12 I 0
12:2= 6 I 0
6:2= 3 I 0
3:2=1 I 1
1:2= 0 I 1
czytamy od dołu i wychodzi, że 99₁₀ = 1100011₂
155:2= 77 I 1
77:2=38 I 1
38:2= 19 I 0
19:2=9 I 1
9:2=4 I 1
4:2=2 I 0
2:2=1 I 0
1:2=0 I 1
155=10011011
1299:2= 649 I 1
649:2= 324 I 1
324:2= 162 I 0
162:2= 81 I 0
81:2= 40 I 1
40:2=20 I 0
20:2=10 I 0
10:2=5 I 0
5:2=2 I 1
2:2=1 I 0
1:2=0 I 1
1299=10100010011