Mencari luas permukaan:
r = 14 ÷ 2 = 7 cm
Selubung tabung:
L = π × r × (r + 2 × t)
= 22/7 × 7 × (7 + 2 × 10)
= 22/7 × 7 × (7 + 20)
= 22/7 × 7 × 27
= 22 × 27
= 594 cm²
Setengah bola:
L = ½ × 4 × π × r²
= ½ × 4 × 22/7 × 7 × 7
= 2 × 22 × 7
= 308 cm²
Luas permukaan:
594 + 308 = 902 cm²
Mencari biaya pengecatan:
902 × 750
= Rp 676.500,-
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Mencari luas permukaan:
r = 14 ÷ 2 = 7 cm
Selubung tabung:
L = π × r × (r + 2 × t)
= 22/7 × 7 × (7 + 2 × 10)
= 22/7 × 7 × (7 + 20)
= 22/7 × 7 × 27
= 22 × 27
= 594 cm²
Setengah bola:
L = ½ × 4 × π × r²
= ½ × 4 × 22/7 × 7 × 7
= 2 × 22 × 7
= 308 cm²
Luas permukaan:
594 + 308 = 902 cm²
Mencari biaya pengecatan:
902 × 750
= Rp 676.500,-
Jawaban: D.