zadanie
x do potegi 3 -3x do potegi 2 +5x-15=0 jedna z przyprostokatnych trojkata prostokatnego ma dlugosc 8 a preciw prostokatna 10 oblicz miary jego katow ostrych
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z.1
x^3 - 3 x^2 + 5 x - 15 = 0
x^2 *( x - 3) + 5*( x - 3) = 0
( x ^2 + 5)*( x - 3) = 0
x - 3 = o
x = 3
======, x^2 + 5 > 0 dla dowolnej liczby rzeczywistej x
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z.2
b = 8
c = 10
zatem
cos alfa = b/c = 8/10 = 0,8
alfa = 36 stopni 50 minut
======================== ( z tablic )
beta = 90 st - alfa = 90 st - 36 st 50 min = 53 st 10 min
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1) x³-3x²+5x-15=0
x²(x-3)+5(x-3)=0
(x-3)(x²+5)=0
x-3=0 ∨ x ²+5=0 rownanie sprzeczne
x=3
Pierwiastkiem rownania jest liczba 3
===================================================
2) a=8
c=10
α=?
β=?
sinα=a/c
sinα=0,8000
α≈53 st
α+β=90 st
β=90 st-53 st
β≈37 st
Miary katow ostrych wynosza w przyblizeniu 53 st i 37 st