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a odleglosc AD policzyc z twierdzenia Carnota [cosinusow]
|AB|=√3 α=60°
|AB|=|AC|√2⇒AC=√3/√2
AC=DC
AD²=2·|AC|²-2·|AC|²·cos60°=|AC|² trojkat rownoboczny
ODP AD=√(1,5)
b)
|BC|=1 α=120° cos120°=-1/2
AC=1
AD²=2·|AC|²-2·|AC|²·cos120°=3|AC|²
AD=|AC|√3=√3