Zadanie w zalączniku. wystarczy jedno, ale prosze o dokładne rozwiązanie.
Za więcej niż jedno daje naj
2. x²+y²-8x-4 = 0
(x-4)² + y² = 20
S(4,0)
r = 2√5
x+2y-14 = 0
x = 14 - 2y
(14 - 2y-4)² + y² = 20
100 - 40y + y²+y²-20 = 0
2y² - 40y + 80 = 0
Δ = (-40)² -80*2*4 = 1600-640 = 1600-640 = 960
√Δ = 8√15
y₁ = 40-8√15/4 = 10-2√15
y₂ = 40+8√15/4 = 10+2√15
x₂ = 14-2*(10+2√15) =-4√15-6
x ₁= 14-2*(10-2√15) = -6+4√15
A(-6+4√15, 10-2√15)
B(-4√15-6, 10+2√15)
C(4√15+6, -10-2√15)
D(6-4√15, -10+2√15
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2. x²+y²-8x-4 = 0
(x-4)² + y² = 20
S(4,0)
r = 2√5
x+2y-14 = 0
x = 14 - 2y
(14 - 2y-4)² + y² = 20
100 - 40y + y²+y²-20 = 0
2y² - 40y + 80 = 0
Δ = (-40)² -80*2*4 = 1600-640 = 1600-640 = 960
√Δ = 8√15
y₁ = 40-8√15/4 = 10-2√15
y₂ = 40+8√15/4 = 10+2√15
x₂ = 14-2*(10+2√15) =-4√15-6
x ₁= 14-2*(10-2√15) = -6+4√15
A(-6+4√15, 10-2√15)
B(-4√15-6, 10+2√15)
C(4√15+6, -10-2√15)
D(6-4√15, -10+2√15