zadanie w załączniku.
trzeba coś wpisać w to okienko z boku ;D
(4\sqrt{2} )^{2} +b^2=(3\sqrt{5})^2
32+b^2=45
45-32=b^2
13=b^2
b= \sqrt{13}
pole kwadratu = a^2
a=(\sqrt{13})^2
pole = 13 jednostek kwadratowych
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(4\sqrt{2} )^{2} +b^2=(3\sqrt{5})^2
32+b^2=45
45-32=b^2
13=b^2
b= \sqrt{13}
pole kwadratu = a^2
a=(\sqrt{13})^2
pole = 13 jednostek kwadratowych