zadanie w załączniku...logarytmy...dziękuję za pomoc
loga √(ab) = loga(ab)¹/² = ½·log(ab) = ½·(loga a + loga b) = ½·(1 + 5) = ½ · 6 = 3
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loga √(ab) = loga(ab)¹/² = ½·log(ab) = ½·(loga a + loga b) = ½·(1 + 5) = ½ · 6 = 3