Question

zadanie w załączniku

Answer 1

a)3⁻¹=(⅓)¹=⅓

5⁻²=(⅕)²=1/25

2⁻³=(½)³=⅛

 

b)(7/11)⁻¹=11/7=1⁴/₇

(⅓)⁻²=3²=9

(¾)⁻²=(4/3)²=16/9

 

C)2,5⁻¹=(2½)⁻¹=(5/2)⁻¹=⅖

(0,4)⁻²=(⅖)⁻²=(5/2)²=25/4

1,25⁻¹=(1¼)⁻¹=(5/4)⁻¹=⅘

 

d)(-10)⁻⁵=(-1/10)⁵=-1/100000

(-4)⁻²=(-¼)²=1/16

(-2)⁻³=(-½)³=-⅛

 

e)(-⅔)⁻²=(-3/2)²=9/4

(-⅕)⁻³=(-5)³=-125

(-3⅓)⁻⁴=(-10/3)⁻⁴=(-3/10)⁴=81/10000

 

f)(-1.2)⁻¹=(-1⅕)⁻¹=(-6/5)⁻¹=-⅚

(-0,1)⁻⁵=(-1/10)⁻⁵=(-10)⁵=-100 000

(-0,02)⁻⁴=(-1/50)⁻⁴=(-50)⁴=6 250 000