Zadanie w załączniku, proszę o szybką pomoć, z góry dziękuję!
a) 5x / (x - 4) = 0 ⇔ x ≠ 4
b) √16 = 4 ⇔ 4² = 16
c) x² = 1 ⇔ x = 1 lub x = -1
d) x * y ≠ 0 ⇔x ≠ 0 i y ≠ 0
e) |x| = 3 ⇔ x = -3 lub x = 3
f) x ≠ - 5 i x ≠ 5 ⇔ (x - 1) / (x² - 25) = 0
g) ∛(-27) = -3 ⇔ (-3)³ = -27
a)
x+1/x-4 = 0 <=> x ≠ 4
b)
√16 = 4 <=> 4² = 16
c)
x² = 1 <=> x = -1 v x = 1
d)
x·y ≠ 0 <=> x ≠ 0 i y ≠ 0
e)
IxI = 3 <=> x = -3 v x = 3
f)
x ≠-5 i x ≠ 5 <=> x/(x-5)(x+5) = 0
g)
∛(-27) = -3 <=> (-3)³ = -27
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a) 5x / (x - 4) = 0 ⇔ x ≠ 4
b) √16 = 4 ⇔ 4² = 16
c) x² = 1 ⇔ x = 1 lub x = -1
d) x * y ≠ 0 ⇔x ≠ 0 i y ≠ 0
e) |x| = 3 ⇔ x = -3 lub x = 3
f) x ≠ - 5 i x ≠ 5 ⇔ (x - 1) / (x² - 25) = 0
g) ∛(-27) = -3 ⇔ (-3)³ = -27
a)
x+1/x-4 = 0 <=> x ≠ 4
b)
√16 = 4 <=> 4² = 16
c)
x² = 1 <=> x = -1 v x = 1
d)
x·y ≠ 0 <=> x ≠ 0 i y ≠ 0
e)
IxI = 3 <=> x = -3 v x = 3
f)
x ≠-5 i x ≠ 5 <=> x/(x-5)(x+5) = 0
g)
∛(-27) = -3 <=> (-3)³ = -27