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b=√27- (9⁻³ /3⁻⁵)
√27= 27|3
9|3
3|3
1
√27=3√3
b=3√3 - [(3²)⁻³/3⁻⁵]= 3√3- [3⁻⁶/3⁻⁵]=3√3-3⁻¹=3√3-1/3= (9√3-1)/3
a= (3√3-4) / (1+2√3)· (1-2√3)/(1-2√3)=(3√3-4)(1-2√3)/ (1-12)= (3√3-18-4+8√3)/ -11= (11√3-22)/-11
a= - (11√3-22)/11
a+b=- (11√3-22)/11 + (9√3-1)/3= -3(11√3-22)/33+ 11(9√3-1)/33=(-33√3+66+99√3-11)/ 33= (66√3+55)/33= (6√3+5)/3
(6√3+5)/3-------80%
c -----------------100%
c= [100·(6√3+5)/3 ] : 80= (30√3+25) / 12