Question

Zadanie w załączniku. PILNE!

Answer 1

2. K3PO4= 212 g/mol
    40----x mola
    212----1mol 

  x=0,18 mola
  Cm=n/v
   Cm= 0,18mola/3dm3= 0,06 mol/dm3

3. Cp1= 6% 
   mr=1500g
    Cp2=3%

 ms=mr*Cp/100%=1500g*3%/100%=45g

 45/6%=750g tyle trzeba octu 6%
do 1.5kg dolewamy m=1500g-750g-750g wody
 

 WODA- 750g
 OCET - 750g 

Answer 2

zad1.

dane:

ms=40g

v=3000cm3=3dm3

M=212/mol

 

n=ms/M

n=40/212

n=0.188

 

Cm=n/v

Cm=0.188/3

Cm=0.062 mol/dm3

zad2.

dane:

Cp1=6%

mr=1500g

Cp2=3%

 

ms=cp*mr/100 ze wzoru

ms=1500*3/100

ms=45g

ms2=45/6

ms2=750 g

 

mr2=ms*100/cp

mr2=4500/6

mr2=750g

 mw=mr-ms

mw=1500g-750=750g H20

 

750g wody i 750g octu

Pozdrawiam :)

Kasia.