Zadanie o treści: Oblicz: |x^2 - 25| + |x + 5| = 5
|x^2 - 25| + |x + 5| = 5
|(x - 5)(x+5| + |x + 5| = 5
A B C
x:-∞-----------(-5)----------------(5)--------->∞
x-5 - - - 0 +
x+5 - 0 + + +
=================================
A:x∈(-∞,-5) ⇒ x²-25-x-5=5
B:x∈[-5,5) ⇒ -x²+25+x+5=5
C:x∈[5,+∞) ⇒ x²-25+x+5=0
===============================
A: x²-x-35=0
Δ=1+141=141
√Δ=√141≈11,9
x1=(1-√141)/2≈-5.4 OK nalezy do A
x2=(1+√141)/2≈-6.4 NIE nalezy do A
.....................................................................
B: -x²+x+25=0
Δ=1+100=101
√Δ=√101≈10
x1=(-1-√101)/(-2)≈5,52 NIE nalezy do B
x2=(-1+√101)/(-2)≈-4,52 OK nalezy do B
..........................................................................
C: x² - 25+x + 5= 5
x² +x -2 5= 0
Δ=101
x1=(-1-√101)/2=-5,52 NIE nalezy do C
x2=(-1+√101)/2=4,52 NIE nalezy do C
ODP
x=(1-√141)/2≈-5.4 ∨ x=(-1+√101)/(-2)≈-4,52
Pozdrawiam
Hans
Moze zainteresuje Cie program do wykresow i grafiki
http://l5.pk.edu.pl/~kraus/bryly_3d/mini_plot.php
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|x^2 - 25| + |x + 5| = 5
|(x - 5)(x+5| + |x + 5| = 5
A B C
x:-∞-----------(-5)----------------(5)--------->∞
x-5 - - - 0 +
x+5 - 0 + + +
=================================
A:x∈(-∞,-5) ⇒ x²-25-x-5=5
B:x∈[-5,5) ⇒ -x²+25+x+5=5
C:x∈[5,+∞) ⇒ x²-25+x+5=0
===============================
A: x²-x-35=0
Δ=1+141=141
√Δ=√141≈11,9
x1=(1-√141)/2≈-5.4 OK nalezy do A
x2=(1+√141)/2≈-6.4 NIE nalezy do A
.....................................................................
B: -x²+x+25=0
Δ=1+100=101
√Δ=√101≈10
x1=(-1-√101)/(-2)≈5,52 NIE nalezy do B
x2=(-1+√101)/(-2)≈-4,52 OK nalezy do B
..........................................................................
C: x² - 25+x + 5= 5
x² +x -2 5= 0
Δ=101
x1=(-1-√101)/2=-5,52 NIE nalezy do C
x2=(-1+√101)/2=4,52 NIE nalezy do C
ODP
x=(1-√141)/2≈-5.4 ∨ x=(-1+√101)/(-2)≈-4,52
Pozdrawiam
Hans
Moze zainteresuje Cie program do wykresow i grafiki
http://l5.pk.edu.pl/~kraus/bryly_3d/mini_plot.php