Zadanie jest w zalaczniku
1
10/x = tgα
10/x = tg25
10/x = 0,4663
x = 21,45 = 21,5 cm
0,5x/8 = cos 70
0,5x/8 = 0,3420
0,5x = 2,736
x = 5,47 = 5,5 cm
2
4/8 = tgα
tgα = 0,5
z tablic α = 27 stopni
a/2,5a = cosα
0,4 = cosα
α = 66 stopni
3
h=34
α = 26stopni
x -------------odległość
34/x = tg 26
34/ x = 0,4877
x = 34:0,4877
x = 69,71 metrów
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1
10/x = tgα
10/x = tg25
10/x = 0,4663
x = 21,45 = 21,5 cm
0,5x/8 = cos 70
0,5x/8 = 0,3420
0,5x = 2,736
x = 5,47 = 5,5 cm
2
4/8 = tgα
tgα = 0,5
z tablic α = 27 stopni
a/2,5a = cosα
0,4 = cosα
α = 66 stopni
3
h=34
α = 26stopni
x -------------odległość
34/x = tg 26
34/ x = 0,4877
x = 34:0,4877
x = 69,71 metrów