[tex]\sqrt{19-6\sqrt{2}} = \sqrt{(18-6\sqrt{2}+1)} = \sqrt{(3\sqrt{2}-1)^2} = |3\sqrt{2}-1| = 3\sqrt{2}-1\\ \\3\sqrt{2}-1-3\sqrt{2}+1 = 0[/tex]
zatem liczby są przeciwne
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[tex]\sqrt{19-6\sqrt{2}} = \sqrt{(18-6\sqrt{2}+1)} = \sqrt{(3\sqrt{2}-1)^2} = |3\sqrt{2}-1| = 3\sqrt{2}-1\\ \\3\sqrt{2}-1-3\sqrt{2}+1 = 0[/tex]
zatem liczby są przeciwne