Question

Zadanie 2 oraz 3 proszę pomóżcie mi xd

Answer 1

Zad 2
a)
2³ * 4⁶ = 2³ * (2²)⁶ = 2³ * 2¹² = 2¹⁵
b)
4⁻⁵ * 8² = (2²)⁻⁵ * (2³)² = 2⁻¹⁰ * 2⁶ = 2⁻⁴
c)
64² : 32⁻³ = (2⁶)² : (2⁵)⁻³ = 2¹² : 2⁻¹⁵ = 2²⁷
d)
(16⁻² : 4⁻⁸) = [(2⁴)⁻² : (2²)⁻⁸] = (2⁻⁸ : 2⁻¹⁶) = 2⁸
zad 3
a)
2⁴ , 2⁻⁴ , 2⁹ , 2² , 2²⁰
b)
3⁻⁴ , 3³ , 3⁻⁴ , 3³ , 3⁻²⁰
c)
(0,1)³ , (0,1)⁻¹⁰ , (0,1)⁻⁸ , (0,1)⁶
d)
5⁻⁶ , 5² , 5⁻¹² , 5⁻²⁰
zad 4
a)
(- 2√3)⁻³ = (- 1/2√3)³ = - 1/8√27 = - 1/24√3 = - √3/24 * 3 = - √3/72
b)
(3/√2)⁻⁴ = (√2/3)⁴ = (√16/81) = 4/81
c)
( - √5/10)⁻³ = (- 10/√5)³ = - 1000/√125 = 1000/5√5 = 200/√5 = 200√5/5 = 40√5
d)
[(- 3√2)]⁻¹ = - 1/3√2 = - √2/3 * 2 = - √2/6