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3)
f(x) = ax² + bx + c
f(-6) = -1
f(0) = -1
p=- 6+0/2 = -3
q = -2
f(x) = a(x-p)² + q
f(x) = a(x+3)² - 2=a(x² + 6x + 9) - 2 = ax² + 6ax + 9a - 2
f(0) = -1
-1 = 9a - 2
a = 1/9
Odp. f(x) = 1/9x² + 2/3x -1
4) y = ½x² + 5x - 1
p = -5/1 = -5
q = f(p) = = f(-5) = ½ * 25 - 25 - 1 = 12½ - 26 = -13½
postać kanoniczna: y = ½(x +5)² - 13½
8) y = x² + 5x + 2
y = - x - 6
x² + 5x + 2 = -x -6
x² + 6x + 8 = 0
Δ = 36 -32 = 4
√Δ = 2
X1 = -6-2/2 = -4
X2 = -6+2/2 = -2
x=-4 lub x=-2
y=-2 y=-4
Odp. A(-4,-2), B(-2,-4)
11)
a) f(0) = - 0,35 * 0 + 2 * 0 + 0,6 = 0,6m
c) q = ?
Δ= 4 - 4*(-0,35)*0,6=4+0,84=4,84
q = -4,84/4*(-0,35) = 3,457143 = 3 i 16/35m